support bazel complie this project and format code.

practical_exercises/10_day_practice/day10/file/10-4.cpp

@@ -0,0 +1,30 @@
+#include <iostream>
+using namespace std;
+
+int main(int argc, char const *argv[]) {
+  char c[30] = "this is string";
+  double d = -1231.232;
+  cout.width(30);
+  cout.fill('*');
+  cout.setf(ios::left);
+  cout << c << "----L1" << endl;
+  cout.width(30);
+  cout.fill('-');
+  cout.setf(ios::right);
+  cout << c << "----L2" << endl;
+  cout.setf(ios::dec | ios::showbase | ios::showpoint);
+  cout.width(30);
+  cout << d << "----L3"
+       << "\n";
+  cout.setf(ios::showpoint);
+  cout.precision(10);
+  cout.width(30);
+  cout << d << "----L4"
+       << "\n";
+  cout.width(30);
+  cout.setf(ios::oct, ios::basefield);
+  cout << 100 << "----L5"
+       << "\n";
+  
+  return 0;
+}

practical_exercises/10_day_practice/day10/file/12-1.cpp

@@ -0,0 +1,17 @@
+//用cin输入字符串数据时，如果字符串中含有空白就不能完整输入。因为遇到空白字符时，cin就认为字符串结束了。
+#include <iostream>
+using namespace std;
+int main(int argc, char const *argv[]) {
+  char a[50];
+  cout << "please input a string:";
+  cin >> a;
+  cout << a << endl;
+  
+  return 0;
+}
+/*
+若a的内容是：
+this is a string!
+就难以输入啦！
+这样的数据应用输入流类的成员函数输入
+*/

practical_exercises/10_day_practice/day10/file/12-2.cpp

@@ -0,0 +1,12 @@
+#include <iostream>
+using namespace std;
+int main(int argc, char const *argv[]) {
+  char stu[5][10];
+  int i;
+  for (i = 0; i < 5; i++)
+    cin.getline(stu[i], 10, ',');
+  for (i = 0; i < 5; i++)
+    cout << stu[i] << endl;
+  
+  return 0;
+}

practical_exercises/10_day_practice/day10/file/12-3.cpp

@@ -0,0 +1,19 @@
+#include <iostream>
+using namespace std;
+//函数原型
+// put(char c)
+// write(const char*c, int n)
+int main() {
+  char c;
+  char a[50] = "this is a string...";
+  cout << "use get() input char:";
+  while ((c = cin.get()) != '\n') {
+    cout.put(c);
+    cout.put('\n');
+    cout.put('t').put('h').put('i').put('s').put('\n');
+    cout.write(a, 12).put('\n');
+    cout << "look"
+         << "\t here!" << endl;
+  }
+  
+}

practical_exercises/10_day_practice/day10/file/12-5.cpp

@@ -0,0 +1,20 @@
+// Eg12-5.cpp
+#include <iomanip>
+#include <iostream>
+using namespace std;
+int main() {
+  char c[30] = "this is string";
+  double d = -1234.8976;
+  cout << setw(30) << left << setfill('*') << c << "----L1" << endl;
+  cout << setw(30) << right << setfill('*') << c << "----L2" << endl;
+  // showbase显示数值的基数前缀
+  cout << dec << showbase << showpoint << setw(30) << d << "----L3"
+       << "\n";
+  // showpoint显示小数点
+  cout << setw(30) << showpoint << setprecision(10) << d << "----L4"
+       << "\n";
+  // setbase(8)设置八进制
+  cout << setw(30) << setbase(16) << 100 << "----L5"
+       << "\n";
+  
+}

practical_exercises/10_day_practice/day10/file/12-6.cpp

@@ -0,0 +1,37 @@
+// 12-6.cpp
+#include <fstream>
+#include <iostream>
+using namespace std;
+int main(int argc, char const *argv[]) {
+  fstream ioFile;
+  ioFile.open("./a.dat", ios::out);
+  ioFile << "张三"
+         << "  " << 76 << " " << 98 << " " << 67 << endl; // L3
+  ioFile << "李四"
+         << "  " << 89 << " " << 70 << " " << 60 << endl;
+  ioFile << "王十"
+         << "  " << 91 << " " << 88 << " " << 77 << endl;
+  ioFile << "黄二"
+         << "  " << 62 << " " << 81 << " " << 75 << endl;
+  ioFile << "刘六"
+         << "  " << 90 << " " << 78 << " " << 67 << endl;
+  ioFile.close();
+  ioFile.open("./a.dat", ios::in | ios::binary);
+  char name[10];
+  int chinese, math, computer;
+  cout << "姓名\t"
+       << "英语\t"
+       << "数学\t"
+       << "计算机\t"
+       << "总分" << endl;
+  ioFile >> name;
+  while (!ioFile.eof()) {
+    ioFile >> chinese >> math >> computer;
+    cout << name << "\t" << chinese << "\t" << math << "\t" << computer << "\t"
+         << chinese + math + computer << endl;
+    ioFile >> name;
+  }
+  ioFile.close();
+  
+  return 0;
+}

practical_exercises/10_day_practice/day10/file/12-7.cpp

@@ -0,0 +1,20 @@
+// Eg12-7.cpp
+#include <fstream>
+#include <iostream>
+using namespace std;
+int main() {
+  char ch;
+  ofstream out("/test.dat", ios::out | ios::binary); // L1
+  for (int i = 0; i < 90; i++) {
+    if (i > 0 && (i % 30) == 0)
+      out.put('\n');
+    out.put(i);
+    out.put(' ');
+  }
+  out.close();
+  ifstream in("/test.dat", ios::in | ios::binary);
+  while (in.get(ch))
+    cout << ch;
+  in.close();
+  
+}

practical_exercises/10_day_practice/day10/file/12-9.cpp

@@ -0,0 +1,45 @@
+// Eg12-12.cpp
+#include <cstring>
+#include <fstream>
+#include <iostream>
+using namespace std;
+class Employee {
+private:
+  int number, age;
+  char name[20];
+  double sal;
+
+public:
+  Employee() {}
+  Employee(int num, char *Name, int Age, double Salary) {
+    number = num;
+    strcpy(name, Name);
+    age = Age;
+    sal = Salary;
+  }
+  void display() {
+    cout << number << "\t" << name << "\t" << age << "\t" << sal << endl;
+  }
+};
+
+int main() {
+  ofstream out("D:/Employee.dat", ios::out); //定义随机输出文件
+  Employee e1(1, "张三", 23, 2320);
+  Employee e2(2, "李四", 32, 3210);
+  Employee e3(3, "王五", 34, 2220);
+  Employee e4(4, "刘六", 27, 1220);
+  out.write((char *)&e1, sizeof(e1)); //按e1,e2,e3,e4顺序写入文件
+  out.write((char *)&e2, sizeof(e2));
+  out.write((char *)&e3, sizeof(e3));
+  out.write((char *)&e4, sizeof(e4));
+
+  //下面的代码将e3（即王五）的年龄改为40岁
+  Employee e5(3, "王五", 40, 2220);
+  out.seekp(
+      2 *
+      sizeof(
+          e1)); //指针定位到第3（起始为0）个数据块，这里写错了应该是2*sizeof（e1）
+  out.write((char *)&e5, sizeof(e5)); //将e5写到第3个数据块位置，覆盖e3
+  out.close();                        //关闭文件
+  
+}

practical_exercises/10_day_practice/day10/file/BUILD

@@ -0,0 +1,48 @@
+# please run `bazel run //practical_exercises/10_day_practice/day10/file:12-9`
+# please run `bazel run //practical_exercises/10_day_practice/day10/file:12-6`
+# please run `bazel run //practical_exercises/10_day_practice/day10/file:10-4`
+# please run `bazel run //practical_exercises/10_day_practice/day10/file:12-2`
+# please run `bazel run //practical_exercises/10_day_practice/day10/file:practice`
+# please run `bazel run //practical_exercises/10_day_practice/day10/file:12-1`
+# please run `bazel run //practical_exercises/10_day_practice/day10/file:12-5`
+# please run `bazel run //practical_exercises/10_day_practice/day10/file:12-3`
+# please run `bazel run //practical_exercises/10_day_practice/day10/file:12-7`
+
+load("@rules_cc//cc:defs.bzl", "cc_binary")
+
+cc_binary(
+    name = "12-9",
+    srcs = ["12-9.cpp"],
+)
+cc_binary(
+    name = "12-6",
+    srcs = ["12-6.cpp"],
+)
+cc_binary(
+    name = "10-4",
+    srcs = ["10-4.cpp"],
+)
+cc_binary(
+    name = "12-2",
+    srcs = ["12-2.cpp"],
+)
+cc_binary(
+    name = "practice",
+    srcs = ["practice.cpp"],
+)
+cc_binary(
+    name = "12-1",
+    srcs = ["12-1.cpp"],
+)
+cc_binary(
+    name = "12-5",
+    srcs = ["12-5.cpp"],
+)
+cc_binary(
+    name = "12-3",
+    srcs = ["12-3.cpp"],
+)
+cc_binary(
+    name = "12-7",
+    srcs = ["12-7.cpp"],
+)

practical_exercises/10_day_practice/day10/file/input/BUILD

@@ -0,0 +1,18 @@
+# please run `bazel run //practical_exercises/10_day_practice/day10/file/input:getline`
+# please run `bazel run //practical_exercises/10_day_practice/day10/file/input:get2`
+# please run `bazel run //practical_exercises/10_day_practice/day10/file/input:get`
+
+load("@rules_cc//cc:defs.bzl", "cc_binary")
+
+cc_binary(
+    name = "getline",
+    srcs = ["getline.cpp"],
+)
+cc_binary(
+    name = "get2",
+    srcs = ["get2.cpp"],
+)
+cc_binary(
+    name = "get",
+    srcs = ["get.cpp"],
+)

practical_exercises/10_day_practice/day10/file/input/get.cpp

@@ -0,0 +1,20 @@
+//【例12-2】  用函数get和getline读取数据。
+#include <iostream>
+using namespace std;
+int main() {
+  char a, b, c, d;
+  cin.get(a);
+  cin.get(b);
+  c = cin.get();
+  d = cin.get();
+  cout << int(a) << ',' << int(b) << ',' << int(c) << ',' << int(d) << endl;
+  
+  return 0;
+}
+
+/*
+用法：a = cin.get() ?或者 ?cin.get(a)
+结束条件：输入字符足够后回车
+说明：这个是单字符的输入，用途是输入一个字符，把它的ASCALL码存入到a中
+处理方法：与cin不同，cin.get()在缓冲区遇到[enter]，[space]，[tab]不会作为舍弃，而是继续留在缓冲区中
+*/

practical_exercises/10_day_practice/day10/file/input/get2.cpp

@@ -0,0 +1,44 @@
+
+//【例12-2】  用函数get和getline读取数据。
+#include <iostream>
+using namespace std;
+// cin.get(arrayname,size)  把字符输入到arrayname中，长度不超过size
+int main() {
+  // get()两个参数
+
+  // 1.输入串长<size，输入串长>arraylength，会自动扩张arrayname大小，使能保存所有数据
+  //  char a[10];
+  //  cin.get(a,20);
+  //  cout<<a<<endl;
+  // cout<<sizeof(a)<<endl;
+  // 2.输入串长<size，输入串长<arraylength，把串全部输入，后面补‘\0’
+  // char b[10];
+  // cin.get(b,20);
+  // cout<<b<<endl;//12345，此时数组内数据为‘12345'\0’
+  // cout<<sizeof(b)<<endl;
+  // 3.输入串长>size，先截取size个字符，若还是大于arraylength，则自动扩张arrayname大小，使能保存所有数据
+  // char c[5];
+  // cin.get(c,10);
+  // cout<<c<<endl;
+  // cout<<sizeof(c)<<endl;
+  // 4.输入串长>size，先截取size个字符，若小于arraylength，则把截取串放入数组中，最后补充‘\0’
+  // char d[10];
+  // cin.get(d,5);
+  // cout<<d<<endl;
+  // cout<<sizeof(d)<<endl;
+
+  // get()三个参数
+  /*
+      用法：cin.get(arrayname,size,s)
+     ?把数据输入到arrayname字符数组中，当到达长度size时结束或者遇到字符s时结束
+      注释：a必须是字符数组，即char
+     a[]l类型，不可为string类型；size为最大的输入长度；s为控制，遇到s则当前输入结束缓存区里的s不会被舍弃
+
+  */
+  int i;
+  char e[10];
+  cin.get(e, 8, ',');
+  cout << e;
+  
+  return 0;
+}

practical_exercises/10_day_practice/day10/file/input/getline.cpp

@@ -0,0 +1,38 @@
+#include <iostream>
+using namespace std;
+/*
+（1）cin.getline(arrayname,size)与cin.get(arrayname,size)的区别
+cin.get(arrayname,size)当遇到[enter]时会结束目前输入，他不会删除缓冲区中的[enter]
+cin.getline(arrayname,size)当遇到[enter]时会结束当前输入，但是会删除缓冲区中的[enter]
+*/
+int main() {
+  /*
+      char a[10];
+  char b;
+  cin.get(a,10);
+      cin.get(b);
+  cout<<a<<endl<<int(b);//输入：12345[enter] 输出：12345 【换行】 10*/
+  /*char c[10];
+  char d;
+  cin.getline(c,10);
+  cin.get(d);
+      cout<<c<<endl<<int(d);//输入：12345[enter]a[enter] 输出：12345【换行】97*/
+  // cin.getline(arrayname,size,s)与cin.gei(arrayname,size,s)的区别
+  /*
+  cin.getline(arrayname,size,s)当遇到s时会结束输入，并把s从缓冲区中删除
+  cin.get（arrayname,size,s）当遇到s时会结束输入，但不会删除缓冲区中的s
+  */
+  /*
+   char e[10];
+   char f;
+   cin.get(e,10,',');
+       cin.get(f);
+       cout<<e<<endl<<f;//输入：12345,[enter]
+   输出：12345【换行】，说明：cin,get不会删除缓冲区的，*/
+  char e1[10];
+  char f1;
+  cin.getline(e1, 10, ',');
+  cin.get(f1);
+  cout << e1 << endl << f1; //输入：asd,wqe 输出：asd【换行】w
+  
+}

practical_exercises/10_day_practice/day10/file/practice.cpp

@@ -0,0 +1,64 @@
+#include <fstream>
+#include <iostream>
+//向量是一个能够存放任意类型的动态数组
+#include <cstring>
+#include <vector>
+using namespace std;
+class Person {
+private:
+  char name[20];
+  char id[18];
+  int age;
+  char addr[20];
+
+public:
+  Person() {}
+  Person(char *n, char *pid, int Age, char *Addr) {
+    strcpy(name, n);
+    strcpy(id, pid);
+    age = Age;
+    strcpy(addr, Addr);
+  }
+  void display() {
+    cout << name << "\t" << id << "\t" << age << "\t" << addr << endl;
+  }
+};
+int main(int argc, char const *argv[]) {
+  vector<Person> v;
+  vector<Person>::iterator
+      pos; //声明一个迭代器，来访问vector容器，作用：遍历或者指向vector容器的元素
+  char ch;
+  ofstream out("d:/person.dat", ios::out | ios::app | ios::binary);
+  char Name[20], ID[18], Addr[20];
+  int Age;
+  cout << "------输入个人档案------" << endl << endl;
+  do {
+    cout << "姓名： ";
+    cin >> Name;
+    cout << "身份证号： ";
+    cin >> ID;
+    cout << "年龄： ";
+    cin >> Age;
+    cout << "地址： ";
+    cin >> Addr;
+    Person per(Name, ID, Age, Addr);
+    out.write((char *)&per, sizeof(per));
+    cout << "Enter another Person(y/n)?";
+    cin >> ch;
+  } while (ch == 'y');
+  out.close();
+  ifstream in("d:/person.dat", ios::in | ios::binary); // L9
+  Person s;
+  in.read((char *)&s, sizeof(s));
+  while (!in.eof()) {
+    v.push_back(s);
+    in.read((char *)&s, sizeof(s));
+  }
+  cout << "\n---------从文件中读出的数据--------" << endl << endl; // L15
+  pos = v.begin();
+  for (pos = v.begin(); pos != v.end(); pos++)
+    (*pos).display();
+
+  
+  return 0;
+}